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Circuits and conductors

Series–parallel resistance

Rt=R1+R2R3R2+R3
where
Rt
total resistance (Ω)
R₁
series resistance (Ω)
R₂, R₃
parallel pair resistances (Ω)
Explain this equation

Works out the total resistance of one resistance in series with a parallel pair. A common pattern when reducing real circuits.

Rₜ is the total. R₁ carries the whole current. R₂ and R₃ are the parallel pair that share the current after R₁.

Reduce the parallel pair to one equivalent with product over sum, then add R₁ because it is in series with that equivalent.

Sense check: 10 Ω plus 20 Ω in parallel with 30 Ω gives 10 + 12 = 22 Ω. The total sits above R₁ but below R₁ + R₂ + R₃.

Watch out: do not just add all three. Check which parts actually share both ends before grouping them.

Reduce the parallel part to a single equivalent resistance before adding the series part. Work from the inside of the grouping outward.

R₁ carries total current. After it, current splits between R₂ and R₃ and recombines on return.

Enter your values to see the result.

Common mistake

Adding all three resistances although two are parallel.

Limits

R₁ in series with the parallel pair R₂ and R₃.

Sources

The tools calculate the displayed equation. They do not automatically choose cable sizes, approve installations, supply current regulatory tables, certify equipment or replace inspection and testing.

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